Optimal. Leaf size=269 \[ -\frac{8 i x \cosh \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{PolyLog}\left (2,-i e^{\frac{c}{2}+\frac{d x}{2}}\right )}{d^2 \sqrt{a \cosh (c+d x)+a}}+\frac{8 i x \cosh \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{PolyLog}\left (2,i e^{\frac{c}{2}+\frac{d x}{2}}\right )}{d^2 \sqrt{a \cosh (c+d x)+a}}+\frac{16 i \cosh \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{PolyLog}\left (3,-i e^{\frac{c}{2}+\frac{d x}{2}}\right )}{d^3 \sqrt{a \cosh (c+d x)+a}}-\frac{16 i \cosh \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{PolyLog}\left (3,i e^{\frac{c}{2}+\frac{d x}{2}}\right )}{d^3 \sqrt{a \cosh (c+d x)+a}}+\frac{4 x^2 \tan ^{-1}\left (e^{\frac{c}{2}+\frac{d x}{2}}\right ) \cosh \left (\frac{c}{2}+\frac{d x}{2}\right )}{d \sqrt{a \cosh (c+d x)+a}} \]
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Rubi [A] time = 0.163233, antiderivative size = 269, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 5, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.278, Rules used = {3319, 4180, 2531, 2282, 6589} \[ -\frac{8 i x \cosh \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{PolyLog}\left (2,-i e^{\frac{c}{2}+\frac{d x}{2}}\right )}{d^2 \sqrt{a \cosh (c+d x)+a}}+\frac{8 i x \cosh \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{PolyLog}\left (2,i e^{\frac{c}{2}+\frac{d x}{2}}\right )}{d^2 \sqrt{a \cosh (c+d x)+a}}+\frac{16 i \cosh \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{PolyLog}\left (3,-i e^{\frac{c}{2}+\frac{d x}{2}}\right )}{d^3 \sqrt{a \cosh (c+d x)+a}}-\frac{16 i \cosh \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{PolyLog}\left (3,i e^{\frac{c}{2}+\frac{d x}{2}}\right )}{d^3 \sqrt{a \cosh (c+d x)+a}}+\frac{4 x^2 \tan ^{-1}\left (e^{\frac{c}{2}+\frac{d x}{2}}\right ) \cosh \left (\frac{c}{2}+\frac{d x}{2}\right )}{d \sqrt{a \cosh (c+d x)+a}} \]
Antiderivative was successfully verified.
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Rule 3319
Rule 4180
Rule 2531
Rule 2282
Rule 6589
Rubi steps
\begin{align*} \int \frac{x^2}{\sqrt{a+a \cosh (c+d x)}} \, dx &=\frac{\sin \left (\frac{1}{2} \left (i c+\frac{\pi }{2}\right )+\frac{\pi }{4}+\frac{i d x}{2}\right ) \int x^2 \csc \left (\frac{1}{2} \left (i c+\frac{\pi }{2}\right )+\frac{\pi }{4}+\frac{i d x}{2}\right ) \, dx}{\sqrt{a+a \cosh (c+d x)}}\\ &=\frac{4 x^2 \tan ^{-1}\left (e^{\frac{c}{2}+\frac{d x}{2}}\right ) \cosh \left (\frac{c}{2}+\frac{d x}{2}\right )}{d \sqrt{a+a \cosh (c+d x)}}-\frac{\left (4 i \sin \left (\frac{1}{2} \left (i c+\frac{\pi }{2}\right )+\frac{\pi }{4}+\frac{i d x}{2}\right )\right ) \int x \log \left (1-i e^{\frac{c}{2}+\frac{d x}{2}}\right ) \, dx}{d \sqrt{a+a \cosh (c+d x)}}+\frac{\left (4 i \sin \left (\frac{1}{2} \left (i c+\frac{\pi }{2}\right )+\frac{\pi }{4}+\frac{i d x}{2}\right )\right ) \int x \log \left (1+i e^{\frac{c}{2}+\frac{d x}{2}}\right ) \, dx}{d \sqrt{a+a \cosh (c+d x)}}\\ &=\frac{4 x^2 \tan ^{-1}\left (e^{\frac{c}{2}+\frac{d x}{2}}\right ) \cosh \left (\frac{c}{2}+\frac{d x}{2}\right )}{d \sqrt{a+a \cosh (c+d x)}}-\frac{8 i x \cosh \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{Li}_2\left (-i e^{\frac{c}{2}+\frac{d x}{2}}\right )}{d^2 \sqrt{a+a \cosh (c+d x)}}+\frac{8 i x \cosh \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{Li}_2\left (i e^{\frac{c}{2}+\frac{d x}{2}}\right )}{d^2 \sqrt{a+a \cosh (c+d x)}}+\frac{\left (8 i \sin \left (\frac{1}{2} \left (i c+\frac{\pi }{2}\right )+\frac{\pi }{4}+\frac{i d x}{2}\right )\right ) \int \text{Li}_2\left (-i e^{\frac{c}{2}+\frac{d x}{2}}\right ) \, dx}{d^2 \sqrt{a+a \cosh (c+d x)}}-\frac{\left (8 i \sin \left (\frac{1}{2} \left (i c+\frac{\pi }{2}\right )+\frac{\pi }{4}+\frac{i d x}{2}\right )\right ) \int \text{Li}_2\left (i e^{\frac{c}{2}+\frac{d x}{2}}\right ) \, dx}{d^2 \sqrt{a+a \cosh (c+d x)}}\\ &=\frac{4 x^2 \tan ^{-1}\left (e^{\frac{c}{2}+\frac{d x}{2}}\right ) \cosh \left (\frac{c}{2}+\frac{d x}{2}\right )}{d \sqrt{a+a \cosh (c+d x)}}-\frac{8 i x \cosh \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{Li}_2\left (-i e^{\frac{c}{2}+\frac{d x}{2}}\right )}{d^2 \sqrt{a+a \cosh (c+d x)}}+\frac{8 i x \cosh \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{Li}_2\left (i e^{\frac{c}{2}+\frac{d x}{2}}\right )}{d^2 \sqrt{a+a \cosh (c+d x)}}+\frac{\left (16 i \sin \left (\frac{1}{2} \left (i c+\frac{\pi }{2}\right )+\frac{\pi }{4}+\frac{i d x}{2}\right )\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2(-i x)}{x} \, dx,x,e^{\frac{c}{2}+\frac{d x}{2}}\right )}{d^3 \sqrt{a+a \cosh (c+d x)}}-\frac{\left (16 i \sin \left (\frac{1}{2} \left (i c+\frac{\pi }{2}\right )+\frac{\pi }{4}+\frac{i d x}{2}\right )\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2(i x)}{x} \, dx,x,e^{\frac{c}{2}+\frac{d x}{2}}\right )}{d^3 \sqrt{a+a \cosh (c+d x)}}\\ &=\frac{4 x^2 \tan ^{-1}\left (e^{\frac{c}{2}+\frac{d x}{2}}\right ) \cosh \left (\frac{c}{2}+\frac{d x}{2}\right )}{d \sqrt{a+a \cosh (c+d x)}}-\frac{8 i x \cosh \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{Li}_2\left (-i e^{\frac{c}{2}+\frac{d x}{2}}\right )}{d^2 \sqrt{a+a \cosh (c+d x)}}+\frac{8 i x \cosh \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{Li}_2\left (i e^{\frac{c}{2}+\frac{d x}{2}}\right )}{d^2 \sqrt{a+a \cosh (c+d x)}}+\frac{16 i \cosh \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{Li}_3\left (-i e^{\frac{c}{2}+\frac{d x}{2}}\right )}{d^3 \sqrt{a+a \cosh (c+d x)}}-\frac{16 i \cosh \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{Li}_3\left (i e^{\frac{c}{2}+\frac{d x}{2}}\right )}{d^3 \sqrt{a+a \cosh (c+d x)}}\\ \end{align*}
Mathematica [A] time = 1.70702, size = 163, normalized size = 0.61 \[ \frac{2 i \cosh \left (\frac{1}{2} (c+d x)\right ) \left (-4 d x \text{PolyLog}\left (2,-i e^{\frac{1}{2} (c+d x)}\right )+4 d x \text{PolyLog}\left (2,i e^{\frac{1}{2} (c+d x)}\right )+8 \text{PolyLog}\left (3,-i e^{\frac{1}{2} (c+d x)}\right )-8 \text{PolyLog}\left (3,i e^{\frac{1}{2} (c+d x)}\right )+d^2 x^2 \log \left (1-i e^{\frac{1}{2} (c+d x)}\right )-d^2 x^2 \log \left (1+i e^{\frac{1}{2} (c+d x)}\right )\right )}{d^3 \sqrt{a (\cosh (c+d x)+1)}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.039, size = 0, normalized size = 0. \begin{align*} \int{{x}^{2}{\frac{1}{\sqrt{a+a\cosh \left ( dx+c \right ) }}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} 2 \, \sqrt{2} d^{2} \int \frac{x^{2} e^{\left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}}{\sqrt{a} d^{2} e^{\left (2 \, d x + 2 \, c\right )} + 2 \, \sqrt{a} d^{2} e^{\left (d x + c\right )} + \sqrt{a} d^{2}}\,{d x} + 8 \, \sqrt{2} d \int \frac{x e^{\left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}}{\sqrt{a} d^{2} e^{\left (2 \, d x + 2 \, c\right )} + 2 \, \sqrt{a} d^{2} e^{\left (d x + c\right )} + \sqrt{a} d^{2}}\,{d x} + 16 \, \sqrt{2}{\left (\frac{e^{\left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}}{{\left (\sqrt{a} d^{2} e^{\left (d x + c\right )} + \sqrt{a} d^{2}\right )} d} + \frac{\arctan \left (e^{\left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}\right )}{\sqrt{a} d^{3}}\right )} - \frac{2 \,{\left (\sqrt{2} d^{2} x^{2} e^{\left (\frac{1}{2} \, c\right )} + 4 \, \sqrt{2} d x e^{\left (\frac{1}{2} \, c\right )} + 8 \, \sqrt{2} e^{\left (\frac{1}{2} \, c\right )}\right )} e^{\left (\frac{1}{2} \, d x\right )}}{\sqrt{a} d^{3} e^{\left (d x + c\right )} + \sqrt{a} d^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{x^{2}}{\sqrt{a \cosh \left (d x + c\right ) + a}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{2}}{\sqrt{a \left (\cosh{\left (c + d x \right )} + 1\right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{2}}{\sqrt{a \cosh \left (d x + c\right ) + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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